What is $pq -: 6 + 10$ when $p = 7$ and $q=-3$ ?

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Answer 1 · 2017-03-06T15:05:12

First, rewrite this expression as:

$(pq)/(6 + 10) = (pq)/16$

Now, substitute $7$ for $p$ and $-3$ for $q$ giving:

$(7 * -3)/16 = -21/16$

What is pq -: 6 + 10pq -: 6 + 10 when p = 7p = 7 and q=-3q=-3?