If #pH=8.19#, what is #[H_3O^+]#?

1 Answer
anor277
Mar 7, 2017

#pH=-log_10[H_3O^+]#, so #[H_3O^+]=6.00xx10^-9*mol*L^-1#.

Explanation:

We know that #pH=-log_10[H_3O^+]#

So that if #pH=8.19#, #[H_3O^+]=10^(-8.19)#

#6.00xx10^-9*mol*L^-1#

Would this solution be basic or acidic?

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