How do you solve #abs(2x-3)>1#?
1 Answer
Mar 7, 2017
Explanation:
For 'greater than' inequalities the solution is always in 2 parts.
#2x-3>1color(red)" or " 2x-3<-1# Solving both inequalities.
#• 2x-3>1# add 3 to both sides.
#2xcancel(-3)cancel(+3)>1+3#
#rArr2x>4# divide both sides by 2
#(cancel(2) x)/cancel(2)>4/2#
#rArrx>2#
#color(red)"OR"#
#• 2x-3< -1#
#rArr2x< 2#
#rArrx<1#
#x<1" or " x>2" is the solution"#
