Question

Question #fcdaf

Answer 1

`log(1)=0`

Explanation:

A logarithm is used solve for the exponent of a base that results in a certain value.

Given:

`a^x=y`

then,

`log_a(y)=x`

For a generic 'log' function, it is assumed to be base 10. So, we have the following:

`log(1)` is like saying `10^x=1`

For any base, including 10, raised to the power 0, the result is 1. Therefore, `log(1)=0`