How do you solve #-12< - 4x + ( - 3)#?

1 Answer
Mar 8, 2017

See the entire solution process below:

Explanation:

First, add #color(red)(3)# to each side of the inequality to isolate the #x# term while keeping the inequality balanced:

#-12 + color(red)(3) < -4x + (-3) + color(red)(3)#

#-9 < -4x + 0#

#-9 < -4x#

Now, divide each side of the inequality by #color(blue)(-4)# to solve for #x# while keeping the inequality balanced. However, because we are multiplying or dividing an inequality by a negative term we must reverse the inequality:

#(-9)/color(blue)(-4) color(red)(>) (-4x)/color(blue)(-4)#

#9/4 color(red)(>) (color(blue)(cancel(color(black)(-4)))x)/cancel(color(blue)(-4))#

#9/4 color(red)(>) x#

To solve in terms of #x# we can reverse or "flip" the entire inequality:

#x < 9/4#