Question

Question #f64c3

Answer 1

`2268`

Explanation:

Expanding `(3x^3-1)^9=(x(3x^2-1/x))^9` instead, the equivalent term is the one attached to `x^9`.

Now making `y=x^3` in `(3y-1)^9` will be equivalently the constant associated to the `y^3` term

so making

`1/(3!)d^3/(dx^3)(3y-1)^9 = 1/(3!)9 cdot 8 cdot 7 (3^3)=2268`