Question

What is the vertex of `y = 2(x - 3)^2 + 1`?

Answer 1

`(3,1)`

Explanation:

The answer happens to be in the equation without any work needed!

This equation is already in vertex form. The equation for vertex form is `y=a(x-h)^2+k`

In this equation, `(h,k)` is the vertex. When you look at your equation: `y=2(x-3)^2+1`, the `h,k` is `(3,1)`.

*Note: in vertex form, there is a negative sign in front of the `h`, so you must take whatever h value there is an make is opposite. Thus, your vertex is `(3,1)` and not `(-3,1)`.

Check your answer with a graph!
graph{2(x-3)^2+1 [-3.354, 6.646, -1.18, 3.82]}