Question

How do you find the derivative of `f(x)= sin^5 (2x)`?

Answer 1

I got: `f'(x)=10sin^4(2x)cos(2x)`

Explanation:

I would use the Chain Rule starting from the power of `5` then the `sin` and last the `2x` multiplying each derivative:
`f'(x)=5sin^(5-1)(2x)*cos(2x)*2`
`f'(x)=10sin^4(2x)cos(2x)`