How do you solve #20< 2x + 10< 36#?

1 Answer
Jim G.
Mar 10, 2017

#5 < x<13#

Explanation:

Isolate x in the middle interval and have numeric values on the 2 ends.

subtract 10 from ALL 3 intervals.

#20-10 < 2xcancel(+10)cancel(-10)> 36-10#

#rArr10 < 2x > 26#

divide ALL 3 intervals by 2

#10/2 < (cancel(2) x)/cancel(2) < 26/2#

#rArr5 < x < 13" is the solution"#

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