How do you solve #20< 2x + 10< 36#?
1 Answer
Mar 10, 2017
Explanation:
Isolate x in the middle interval and have numeric values on the 2 ends.
subtract 10 from ALL 3 intervals.
#20-10 < 2xcancel(+10)cancel(-10)> 36-10#
#rArr10 < 2x > 26# divide ALL 3 intervals by 2
#10/2 < (cancel(2) x)/cancel(2) < 26/2#
#rArr5 < x < 13" is the solution"#
