Question

How do you solve `\frac { 3} { x - 2} - \frac { 6} { x } = 1`?

Answer 1

#x=-4, x = 3#

Explanation:

`3/(x-2) -6/x=1`

`(3x-6(x-2))/(x * (x-2)) = 1`

`3x -6x +12 = x^2 -2x`
`-3x +12 = x^2 -2x`
`x^2 +x -12 =0`
`x^2 +4x -3x -12 = 0`
`x(x+4) - 3(x+4) = 0`
`=> (x+4)(x-3)=0`
#=>x=-4, x= 3#