How do you solve #-18+ 5x = - 12x - 1#?

1 Answer
Jim G.
Mar 11, 2017

#x=1#

Explanation:

Collect terms in x on the left side of the equation and numeric values on the right side.

add 12x to both sides.

#-18+5x+12x=cancel(-12x)cancel(+12x)-1#

#rArr-18+17x=-1#

add 18 to both sides.

#cancel(-18)cancel(+18)+17x=-1+18#

#rArr17x=17#

divide both sides by 17

#(cancel(17) x)/cancel(17)=17/17#

#rArrx=1#

#color(blue)"As a check"#

Substitute this value into the equation and if left side equals the right side then it is the solution.

#"left side "=-18+(5xx1)=-18+5=-13#

#"right side "=-(12xx1)-1=-12-1=-13#

#rArrx=1" is the solution"#

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