What is the molarity of 1.5 liters of an aqueous solution that contains 52 grams of lithium fluoride, LiF?

1 Answer
anor277
Mar 12, 2017

#"Molarity"# #=# #"Moles of solute"/"Volume of solution"#

Explanation:

And thus, here, #"Molarity"# #=# #((52*cancelg)/(25.9*cancelg*mol^-1))/(1.5*L)=1.3*mol*L^-1#, with respect to lithium fluoride

Now it is a fact that this solution would have a #pH>7#. Given that #HF(aq)# is a fairly weak acid, why should this be so?

Related questions
See all questions in Molarity
Impact of this question
29280 views around the world
You can reuse this answer
Creative Commons License