How do you find #h(-5)# given #h(n)=n^3+3n^2#?
1 Answer
Mar 12, 2017
Explanation:
To evaluate h( -5) substitute n = - 5 into h( n)
#rArrh(color(red)(-5))=(color(red)(-5))^3+3(color(red)(-5))^2#
#color(white)(xxxxxxx)=-125+(3xx25)#
#color(white)(xxxxxxx)=-125+75#
#color(white)(xxxxxxx)=-50#
