Question

How do you solve `(3k)/27=2/3`?

Answer 1

See the entire solution process below:

Explanation:

Multiply each side of the equation by `color(red)(27)/color(blue)(3)` to solve for `k` while keeping the equation balanced:

`color(red)(27)/color(blue)(3) xx (3k)/27 = color(red)(27)/color(blue)(3) xx 2/3`

`cancel(color(red)(27))/cancel(color(blue)(3)) xx (color(blue)(cancel(color(black)(3)))k)/color(red)(cancel(color(black)(27))) = (color(red)(27) xx 2)/(color(blue)(3) xx 3)`

`k = (color(red)(27) xx 2)/9`

`k = (cancel(color(red)(27))3 xx 2)/color(red)(cancel(color(black)(9)))`

`k = 6`