Question #4ea07

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Answer 1 · 2017-03-13T03:45:37

Denver nickel is valued at $$9$ , and Philadelphia is valued at $$6$ .

Given: The $D$ nickel has a higher value than the $P$ nickel because the fraction size is larger than $1$ . We have two unknown values.

We can write: $D = 3/2 P$

We also know that $D + P = $15$

Then we can substitute the $P$ value for $D$ from the first equation into the second:

$3/2 P + P = $15$

$5/2 P = $15$

$5P = $30$

$P = $6$

$D = 3/2 P$

$2D = 3($6)$

$2D = $18$

$D = $9$

Check: $D + P = $15$

$$9 +$6 = $15$