What values of #x# are not in the domain of the expression #(x+5)/(3x^2+23x-36)#?

Question

629 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-03-13T05:11:32

#D_f in R-{9,-4/3}#

#(x+5)/(3x^2+23x-36)#

The denominator should not be zero.

#3x^2+23x-36!=0#

#3x^2+27x-4x-36!=0#

#(x-9)(3x+4)!=0#

#x!= 9# and #x!=-4/3#

#D_f in R-{9,-4/3}#