How do you solve #x+ 4x + 3( 4x ) \leq 680#?

1 Answer
Mar 13, 2017

“Simplify” it by performing all of the operations to combine the terms. Then collect all of the constants on one side to calculate the variable/unknown on the other side.

Explanation:

#x + 4*x + 3*(4*x) ≤ 680#
#x + 4*x + 12*x ≤ 680# ; #17*x ≤ 680# ; #x ≤ 680/17# ; # **x ≤ 40** #

CHECK: for x = 20 ; #x + 4*x + 3*(4*x) ≤ 680#
#20 + 4*20 + 3*(4*20) ≤ 680# ; #20 + 80 + 240 ≤ 680# ; #340 ≤ 680# TRUE!

(you can do the same for x = 50 to see that 850 ≤ 680 is NOT True, and that at x = 40 , 680 = 680 is true, and the limit)