How do you solve #2+3x=-2(-2x+6)#?

1 Answer
Jim G.
Mar 13, 2017

#x=14#

Explanation:

The first step is to distribute the bracket on the right side.

#2+3x=4x-12#

Collect terms in x on the left side and numeric values on the right side.

subtract 4x from both sides.

#2+3x-4x=cancel(4x)cancel(-4x)-12#

#rArr2-x=-12#

subtract 2 from both sides.

#cancel(2)cancel(-2)-x=-12-2#

#rArr-x=-14#

multiply both sides by - 1

#(-1)xx-x=(-1)xx-14#

#rArrx=14#

#color(blue)"As a check"#

Substitute this value into the equation and if the left side equals the right side then it is the solution.

#"left side "=2+(3xx14)=2+42=44#

#"right side "=-2((-2xx14)+6)=-2(-22)=44#

#rArrx=14" is the solution"#

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