How do you solve #-8( 6k - 6) = 432#?

1 Answer
Mar 13, 2017

See the entire solution process below:

Explanation:

First, expand the terms on the left side of the equation by multiplying each term inside the parenthesis by the term outside the parenthesis:

#color(red)(-8)(6k - 6) = 432#

#(color(red)(-8) xx 6k) - (color(red)(-8) xx 6) = 432#

#-48k - (-48) = 432#

#-48k + 48 = 432#

Next, subtract #color(red)(48)# from each side of the equation to isolate the #k# term while keeping the equation balanced:

#-48k + 48 - color(red)(48) = 432 - color(red)(48)#

#-48k + 0 = 384#

#-48k = 384#

Now, divide each side of the equation by #color(red)(-48)# to solve for #k# while keeping the equation balanced:

#(-48k)/color(red)(-48) = 384/color(red)(-48)#

#(color(red)(cancel(color(black)(-48)))k)/cancel(color(red)(-48)) = -8#

#k = -8#