Question

How much heat, in calories, is given off when 1.25 grams of silver is cooled from 100.0 C to 80.0 C? (The specific heat of silver is 0.057 cal/g C)?

Answer 1

The heat is `=1.425cal`

Explanation:

The heat is

`Q=m*s*DeltaT`

mass, `m=1.25g`

specific heat, `s=0.057calg^-1ºC^-1`

`Delta T=100-80=20ºC`

Heat liberated is `=1.25*0.057*20=1.425cal`