How do you convert #y=3(x-5)^2+5# to standard form?

1 Answer
Jim G.
Mar 14, 2017

#y=3x^2-30x+80#

Explanation:

The equation of a #color(blue)"parabola"# in standard form is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=ax^2+bx+c;a!=0)color(white)(2/2)|)))#

The first step here is to distribute #(x-5)^2# using, say, the FOIL method.

#rArr(x-5)^2=x^2-10x+25#

#rArr3(x^2-10x+25)+5#

#=3x^2-30x+75+5#

#=3x^2-30x+80#

#rArry=3x^2-30x+80larrcolor(red)" in standard form"#

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