How do you factor #4h ^ { 5} - 4h ^ { 4} + 3h ^ { 3} - 3h ^ { 2}#?

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Answer 1 · 2017-03-15T17:30:30

See the entire solution process below:

First, you can factor out an #h^2# from each term to give:

#(h^2 * h^3) - (h^2 * 4h^2) + (h^2 * 3h) - (h^2 - 3) = #

#h^2(h^3 - 4h^2 + 3h - 3)#

Or, you can factor a #4h^4# from the first two terms and a #3h^2# from the second two terms to give:

#(4h^4 * h) - (4h^4 * 1) + (3h^2 * h) - (3h^2 - 1) = #

#4h^4(h - 1) + 3h^2(h - 1) = #

#(h - 1)(4h^4 + 3h^2)#