Question

How do you simplify `\frac { 8n ^ { 2} \cdot 4n } { 4n ^ { 8} }`?

Answer 1

`=8/n^5`

Explanation:

`(8n^2 xx cancel4n)/(cancel4n^8)`

`=(8n^3)/n^8" "larr` subtract the indices.

`=8/n^5`

Answers are usually given with positive indices.