Question

How do you simplify `\frac { ( 6a ^ { 3} b ^ { - 2} ) ^ { - 2} } { ( 4a ^ { - 2} b ) ^ { - 1} }`?

Answer 1

`b^5 /(9a^8)`

Explanation:

The given expression is equivalent to `(4a^(-2)b)/(6a^3 b^(-2))^2`

=`(4b)/a^2 1/(36a^6 b^(-4))`

=`(4b)/a^2 b^4/(36a^6)`

=`b^5 /(9a^8)`