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Answer 1 · 2017-03-16T20:27:01

#-1#

Assumption: You mean #(-3)xx1/3#

Not normally done but you can write -3 as #-3/1#

So we have: #-3/1xx1/3" "=" "(-3xx1)/(1xx3)" "=" "-3/3" "=" "-1#

Answer 2 · 2017-03-16T20:27:32

#-1#

#-3xx1/3#

#=-cancel(3)^1xx1/cancel(3)^1#

#=-1#