Question #b1629

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Question #b1629

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Answer 1 · 2017-03-16T20:39:52

$(-8/3, -5/3) , (2, 3)$

Explanation:

$y=x+1$ => eq-1
$2x^2+y^2=17$ => eq-2
Substitute $x+1$ from 1 for $y$ in 2:
$2x^2+(x+1)^2=17$ => expand:
$2x^2+x^2+2x+1=17$ => simplify:
$3x^2+2x-16=0$ =>factor by grouping:
$3x^2-6x+8x-16=0$
$3x(x-2)+8(x-2)=0$
$(3x+8)(x-2)=0$
$x=-8/3, 2$ => substitute in 1 solve for $y$ :
$y=-5/3, 3$

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Question #b1629

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