Question

How do you simplify `\frac { 4u ^ { 4} v ^ { 3} } { 2u }`?

Answer 1

`2u^3v^3`

Explanation:

Rules applied: `x^a/x^b=x^(a-b)`

`(2^2*u^4*v^3)/(2*u^1)`

`2^(2-1)*u^(4-1)*v^3`

`rArr2u^3v^3`

Answer 2

`2u^3v^3`

Explanation:

Write as:

`4/2xxu/uxxu^3xxv^3`

`2u^3v^3`