How do you solve #v^ { 2} - 144= 0#?

2 Answers
iceman
Mar 18, 2017

#v=+-12#

Explanation:

#v^2-144=0#
#(v-12)(v+12)=0#
#v=+-12#

EZ as pi
Mar 18, 2017

#v = +-12#

Explanation:

If a quadratic does not have an #x# term, it can be solved by moving the constant to the RHS. This is especially useful if it it not a perfect square.

#v^2 -144=0#

#v = +-sqrt144#

#v = +-12#

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