How do you factor #4t ^ { 5} + 8t ^ { 4} - 8t ^ { 3} - 16t ^ { 2}#?

1 Answer
Narad T.
Mar 18, 2017

The answer is #=4t^2(t^2-2)(t+2)#

Explanation:

We start by grouping the first term and the third term, and the second term and the fourth

#4t^5+8t^4-8t^3-16t^2#

#=(4t^5-8t^3)+(8t^4-16t^2)#

#=4t^3(t^2-2)+8t^2(t^2-2)#

#=(t^2-2)(4t^3+8t^2)#

#=4t^2(t^2-2)(t+2)#

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