How do you solve #abs(10+7x)>=11#?
2 Answers
Mar 19, 2017
Explanation:
Mar 19, 2017
Explanation:
This inequality is of the form.
#|x|>=arArrxcolor(red)(>=)a" or " xcolor(red)(<=)-a# There are 2 possible solutions here.
#10+7xcolor(red)(>=)11" or " 10+7xcolor(red)(<=)-11#
#color(blue)"Solving " 10+7x>=11# subtract 10 from both sides.
#cancel(10)cancel(-10)+7x>=11-10#
#rArr7x>=1# divide both sides by 7
#(cancel(7) x)/cancel(7)>=1/7#
#rArrx>=1/7larrcolor(red)" first solution"#
#color(blue)"Solving " 10+7x<=-11#
#rArr7x<=-21#
#rArrx<=-3larrcolor(red)" second solution"#