A charge of #12 C# passes through a circuit every #3 s#. If the circuit can generate #8 W# of power, what is the circuit's resistance?

1 Answer
Mar 19, 2017

The resistance is #=2Omega#

Explanation:

We apply the following equation :

#P=RI^2#

Power, #P=8 W#

Current #=I#

Resistance #=R#

The current is related to the charge

#Q=It#

Charge, #Q=12C#

Time, #t=3s#

Current, #I=Q/t=12/3=4A#

Therefore,

The resistance is

#R=P/I^2=8/4^2=2 Omega#