Question #020d3

1 Answer
Mar 20, 2017

#y = 10 sqrt(x) + 3#

Explanation:

In math-speak you have:

#y' = alpha/sqrtx# where #alpha# is some constant

Compared to your other stuff, This is simple power rule material:

#int x^n dx = (x^(n+1))/(n+1) + C#

It solves as:

#y = 2 alpha sqrt(x) + beta#

  • Applying the #(0,3)# condition:

#3 = 0 + beta implies beta = 3#

  • Applying the #(4,23)# condition:

#23 = 2 alpha cdot (pm 2) + 3 implies alpha = pm 5#

#implies y = pm 10 sqrt(x) + 3#

But it has to go through #(4,23)# so it is:

#implies y = 10 sqrt(x) + 3#