Question

Question #0a25a

Answer 1

Lithium hydroxide has a mass of 24 g per mole, so 2.50 g is 0.104 mole.

Dissolve this in 1.50 L, and the concentration is

`[LiOH] = 0.104 mol -: 1.50 L = 0.0694 "mol"/L`

Since LiOH is a strong base, it ionizes completely

`LiOH rarr Li^+ + OH^-`

Since each one mole of LiOH produces one mole of `OH^-`, the concentration of `OH^-` will be `0.0694` mol/L as well.