Question

Question #fff79

Answer 1

`x=-y^2+y`

`x=y^2-3`

`x=-4`

`V=piint_(-1)^(1.5)[(-y^2+y-(-4))^2-(y^2-3-(-4))^2]dy`

`=(875pi)/32`

`= 85.90292412`

Answer 2

"Find the volume of the solid obtained by rotating the region bounded by the curves `y=x^3`, the `x`-axis and the lines `x=1` and `x=2` turn around the x-axis."

`V=piint_1^2(x^3)^2dx`

`=piint_1^2(x^6)dx`

`=pi[1/7x^7]_1^2`

`=2^7/7-1/7`

`=(255pi)/7`