A container has #16 L# of water in it at #100 ^o C#. An object with a specific heat of #85 (KJ)/(Kg*K)# and a temperature of #180 ^oC# is placed into the container. If the water is completely vaporized, what is the object's mass?

Question

253 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-03-22T07:54:47

The mass is #=5.31kg#

The heat transferred from the object to the water, is equal to the heat used to evaporate the water.

For the object #DeltaT_o=80º#

# m_o C_o (DeltaT_o) = m_w H_w #

Heat of vaporisation of water

#H_w=2257kJkg^-1#

#C_o=85kJkg^-1K^-1#

#m_0 C_o*80 = m_w* 2257 #

#m_o*85*80=16*2257#

#m_o=(16*2257)/(85*80)#

#=5.31kg#