If #h(5-2x) = sqrt(x^2+3x+5)# for all real number #x#, what is the value of #h(3)#?

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Answer 1 · 2017-03-22T09:06:01

#h(3) = 3#

For #h(3)# , we have to find the value of #x#.

#5-2x = 3#

#2x=2#

#x=1#

So,
#h(5-2x) = sqrt(x^2+3x+5)#-------(1)

For #h(3)#, put x =1 in #eq^n 1#

#h(3) = sqrt(1^2+3xx1+5)#

#h(3) = sqrt(1+3+5)#

#h(3) = sqrt(9)#

#h(3) = 3#