Question #d2faf

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Question #d2faf

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Answer 1 · 2017-03-22T10:14:56

$- 5 b$ $-5b$

Explanation:

$5 i \times b i$ $5ixxbi$

$= 5 \times i \times b \times i$ $=5xxixxbxxi$

$= 5 \times b \times i \times i$ $=5xxbxxixxi$

$= 5 b \times i^{2}$ $=5bxxi^2$

$= 5 b i^{2}$ $=5bi^2$

If we are dealing with $complex numbers$ $color(blue)"complex numbers"$

$then i^{2} = {(\sqrt{- 1})}^{2} = - 1$ $"then " i^2=(sqrt(-1))^2=-1$

$\Rightarrow 5 b i^{2}$ $rArr5bi^2$

$= 5 b \times (- 1)$ $=5bxx(-1)$

$= - 5 b$ $=-5b$

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Question #d2faf

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