What is the perimeter of a triangle with corners at (6 ,4 ), (8 ,2 ), and (5 ,7 )?

1 Answer
Mar 22, 2017

Perimeter of Triangle = 11.8216566798 units
(or) √(8) + √(34) + √(10)

Explanation:

Vertices of Triangle are (6,4),(8,2),and (5,7)
Distance = sqrt[(x2-x1)^2+(y2-y1)^2]

Using Distance Formula

Find distance between (6,4),(8,2) and (8,2),(5,7) and (5,7),(6,4)

Then we get,
Distance between (6,4),(8,2) = sqrt8

Distance between (8,2),(5,7) = sqrt34

Distance between (5,7),(6,4) = sqrt10

Add them we get Perimeter of the Triangle

√(8) + √(34) + √(10) = 11.8216566798 units

Reference