How do you divide #\frac { 25a ^ { 4} b ^ { 2} } { 8a ^ { 2} b } \div \frac { 5a b ^ { 3} } { 6a ^ { 3} b }#?

1 Answer
iceman
Mar 23, 2017

#(15a^4)/(4b)#

Explanation:

#(25a^4b^2)/(8a^2b)-:(5ab^3)/(6a^3b)#

#=(25a^4b^2)/(8a^2b)*(6a^3b)/(5ab^3)# => simplify top/bottom:

#=(25a^2b)/8*(6a^2)/(5b^2)# => simplify across:

#=(5a^2)/4*(3a^2)/b# => multiply:

#=(15a^4)/(4b)#

Related questions
Impact of this question
260 views around the world
You can reuse this answer
Creative Commons License