How do you evaluate #-8= \frac { s} { 4} + - 5#?

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Answer 1 · 2017-03-23T11:54:44

See the entire solution process below:

First, add #color(red)(5)# to each side of the equation to isolate the #s# term while keeping the equation balanced:

#-8 + color(red)(5) = s/4 + -5 + color(red)(5)#

#-3 = s/4 + 0#

#-3 = s/4#

Now, multiply each side of the equation by #color(red)(4)# to solve for #s# while keeping the equation balanced:

#color(red)(4) xx -3 = color(red)(4) xx s/4#

#-12 = cancel(color(red)(4)) xx s/color(red)(cancel(color(black)(4)))#

#-12 = s#

#s = -12#