How do you solve #23w ^ { 2} + 12w = 0#?

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Answer 1 · 2017-03-24T02:56:28

See the entire solution process below:

First, factor a #w# out of each term on the left side of the equation:

#(w * 23w) + (w * 12) = 0#

#w(23w + 12) = 0#

Now solve each factor for #0#:

Solution 1)

#w = 0#

Solution 2)

#23w + 12 = 0#

#23w + 12 - color(red)(12) = 0 - color(red)(12)#

#23w + 0 = -12#

#23w = -12#

#(23w)/color(red)(23) = -12/color(red)(23)#

#(color(red)(cancel(color(black)(23)))w)/cancel(color(red)(23)) = -12/23#

#w = -12/23#

The solution is: #w = 0# and #w = -12/23#