Question

Question #96a4f

Answer 1

The empirical formula is `"CuS"_2`.

Explanation:

An empirical formula is the simplest whole number molar ratio of the elements in a compound.

Your compound contains `"0.768 mol Cu"` and `"1.56 mol S"`.

I like to summarize the calculations in a table.

`bb("Element"color(white)(m) "Moles"color(white)(m) "Ratio"color(white)(m)color(white)(l)"Integers")`
#color(white)(m)"Cu" color(white)(mmmll)0.768 color(white)(Xm)1color(white)(mmmmmll)1#
`color(white)(m)"S"color(white)(mmmml)1.56" color(white)(Xmll)2.03 color(white)(mmmml)2`

There is 1 mol of `"Cu"` for 2 mol of `"S"`.

The empirical formula is `"CuS"_2`.