Question

If a homozygous dominant genotype is 46% what is the dominant allele frequency?

Answer 1

Well, let's check.

Explanation:

Assuming Hardy-Weinberg conditions are met, we will use the `"Hardy-Weinberg equation"` which is:

`p^2+2pq+q^2=1`

Where:
`p^2 = "frequency of homozygous dominant genotype"`
`2pq = "frequency of heterozygous genotype"`
`q^2 = "frequency of homozygous recessive genotype"`

If a homozygous dominant genotype is `46%`, that means `p^2 = 0.46`

Using `p+q = 1` where:

`p = "frequency of dominant allele"`
`q = "frequency of recessive allele"`

we will find the frequency of the dominant allele, meaning we will solve for `p`.

If we have `p^2` and we need to find `p`, then using basic algebra:

`p^2 = 0.46`
`sqrt(p^2) = sqrt0.46`
`p = 0.68`

the dominant allele frequency turns out to be 0.68 or 68%