Question

Question #17e5c

Answer 1

Train B

Explanation:

Let's focus on Train B. Train B's initial velocity is `8m/s` and acceleration is `1m/s^2`. We also have `t=10` We need Train B's final velocity:

Use the equation `a=(vf-vi)/t`

`1=(vf-8)/10`

`10=vf-8`

`vf=18m/s`

`18m/s` is greater than `16m/s` so Train B goes faster.

Answer 2

Train B

Explanation:

Train A's speed is constant so its speed after 10 seconds would be `16 m/s`, but train B which starts at `8 m/s` accelerates at `1 m/s^2`
so after 10 seconds it picks up additional `10 m/s` of speed to `18 m/s`. Hence B will have greater speed.