A balanced lever has two weights on it, the first with mass $15 k g$ $15 kg$ and the second with mass $80 k g$ $80 kg$ . If the first weight is $16 m$ $16 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2017-03-26T09:41:56

The distance is $= 3 m$ $=3m$

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$M_{2} = 15 g N$ $M_2=15g N$

$b = 16 m$ $b=16m$

$M_{1} = 80 g N$ $M_1=80gN$

Taking moments about the fulcrum

$M_{1} \cdot a = M_{2} \cdot B$ $M_1*a=M_2*B$

$8 o g \cdot b = 15 g \cdot 16$ $8og*b=15g*16$

$b = \frac{15 g \cdot 16}{80 g}$ $b=(15g*16)/(80g)$

$= 3 m$ $=3m$

A balanced lever has two weights on it, the first with mass 15kg15 kg and the second with mass 80kg80 kg. If the first weight is 16m 16 m from the fulcrum, how far is the second weight from the fulcrum?