Question

How do you solve `k^ { 2} + 2= 67`?

Answer 1

We've got `k^2 + 2 = 67`

`implies k^2 = 67 - 2`
`implies k^2 = 65`

Thus, `k = +(65)^(1/2)` and `k = -(65)^(1/2)`

Answer 2

`k = +-sqrt65`

Explanation:

Group like terms by subtracting 2 from both sides of the equation.
`k^2 = 67 - 2`

Simplify
`k^2 = 65`

Take the square root of both sides. Remember when you take the square root, it becomes plus or minus (`+-`). Because either the positive or negative squared will give the positive figure.

`sqrt(k^2) = +-sqrt65`

`k = +-sqrt65`