Question

How do you solve `(u + 2) ( 7u - 6) = 0`?

Answer 1

`u=-2" or " u=6/7`

Explanation:

`"If " axxb=0" then"`

`a=0" or " b=0" or both " a" and " b=0`

`rArr(u+2)(7u-6)=0`

`rArru+2=0rArru=-2" or "`

`7u-6=0rArru=6/7`