Question

How do you solve `e^ { 2x } \geq 5`?

Answer 1

`x>=(ln5)/2`

Explanation:

`e^(2x)>=5` =>take log of both sides(natural log):
`lne^(2x)>=ln5` => simplify using `logx^(y)=ylogx`:
`2xlne>=ln5` => `lne=1`:
`x>=(ln5)/2`