Question

How many ions result from the dissolution of a `11.1*g` mass of calcium chloride in water?

Answer 1

Approx. `1.81xx10^23` ions

Explanation:

`"Moles of calcium chloride"` `=` `(11.1*g)/(110.98*g*mol^-1)=0.100*mol`

And thus in solution:

`CaCl_2(s) + "excess "H_2OrarrCa^(2+) + 2Cl^(-)`, there are `0.100*mol` `Ca^(2+)` ions, and `0.200*mol` `Cl^(-)` ions, i.e. `0.300*mol` of ions...........

And `0.300*molxxN_A=0.300*molxx6.022xx10^23*mol^-1`

`1.81xx10^23` ions..........