How do you solve the system of equations #y=x+1.75# and #4x-2y=4#?

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Answer 1 · 2017-03-27T16:50:49

#x=3.75# #y=5.5#

Plug #x+1.75# into #4x-2y=4# for #y#:

#4x-2x-3.5=4#

Simplify and move 3.5 to the right side:

#2x=7.5#

Solve for x:

#x=3.75#

Plug into the other equation:

#y=3.75+1.75=5.5#